Problems on H.C.F and L.C.M Online Test Part - 9
Exam Name - Quantitative Aptitude
Subject Name - Problems on H.C.F and L.C.M
Exam Type - Multiple Choice Questions
No Of Questions - 10
Subject Name - Problems on H.C.F and L.C.M
Exam Type - Multiple Choice Questions
No Of Questions - 10
Question - 1:The least number which when divided by 5, 6, 8, 9 and 12 leaves a remainder 1 in each case, but when divided by 13 leaves no remainder is :?
- 361
- 721
- 1801
- 3601
Show/Hide Answer
Answer = D - 3601
Explanation: No Explanation
Question - 2:Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively ? Explanation: No Explanation
- 125
- 127
- 129
- 131
Show/Hide Answer
Answer = B - 127
Explanation: No Explanation
Question - 3:Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is ? Explanation: No Explanation
- 40
- 80
- 120
- 200
Show/Hide Answer
Answer = A - 40
Explanation: No Explanation
Question - 4:252 can be expressed as a product of primes as: ? Explanation: No Explanation
- 2 x 2 x 3 x 3 x 7
- 2 x 2 x 2 x 3 x 7
- 3 x 3 x 3 x 3 x 7
- 2 x 3 x 3 x 3 x 7
Show/Hide Answer
Answer = A - 2 x 2 x 3 x 3 x 7
Explanation: No Explanation
Question - 5:The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is ? Explanation: No Explanation
- 22
- 48
- 56
- 27
Show/Hide Answer
Answer = B - 48
Explanation: No Explanation
Question - 6: If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 Explanation: No Explanation
respectively, then the sum of the reciprocals of the numbers is equal to: ?
- 55/601
- 601/55
- 11/120
- 120/11
Show/Hide Answer
Answer = C - 11/120
Explanation: No Explanation
Question - 7:Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.? Explanation: No Explanation
- 4
- 7
- 9
- 13
Show/Hide Answer
Answer = A - 4
Explanation: Required number
= H.C.F of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F of 48, 92 and 140
= 4.
Question - 8:The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: ? Explanation: Required number
= H.C.F of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F of 48, 92 and 140
= 4.
- 504
- 536
- 544
- 548
Show/Hide Answer
Answer = D - 548
Explanation: No Explanation
Question - 9:Product of two co-prime numbers is 117. Their L.C.M should be ? Explanation: No Explanation
- 1
- 117
- equal to their H.C.F
- cannot be calculated
Show/Hide Answer
Answer = B - 117
Explanation: H.C.F of co-prime numbers is 1.
So, L.C.M = 117/1
‹=› 117.
Question - 10:Which of the following is a pair of co-primes ?? Explanation: H.C.F of co-prime numbers is 1.
So, L.C.M = 117/1
‹=› 117.
- (21, 35)
- (23, 92)
- (18, 25)
- (16, 62)
Show/Hide Answer
Answer = C - (18, 25)
Explanation: No Explanation
Explanation: No Explanation






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